The momentum of a particle having de-Bro...

The momentum of a particle having de-Broglie wavelength of `6 Å`

A

`1.1xx10^(34)kg-m//s`

B

`39.6xx10^(-34) kg-m//s`

C

`1.1xx10^(-24)kg-m//s`

D

`39.6xx10^(-24)kg-m//s`

Verified by Experts

The correct Answer is:

C

`p=h/lambda=(6.62xx10^(-34))/(6xx10^(-10))`
`P=1.1xx10^(-24)kg-m//s`

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