How many joules of energy must be absorbed to convert Li to `Li^(+)` , all the atoms present in `1.00` mg of gaseous Li ? `lE_(1)` of Li is `520.3 kJ mol^(-1)(Li=7)` .

Options

A. `0.00743 kJ`
B. `0.520 kJ`
C. `520 kJ`
D. `0.0743 kJ`

Explanation

`1.00 mg=1xx10^(-3)g=(1x10^(-3))/(7)` mol Li
1 mole of Li is converted by `520.3 kJ`.
`therefore(1xx10^(-3))/(7)` mole is converted to `Li^(+)` by
`=(520.3xx1xx10^(-3))/(7)kJ=0.0743 kJ`