The electron affinity values (in `kJ mol^(-1))` of three halogens, `x,y`, and `z`are, respectively, `-349, -333`, and `-325`. Then `x, y`, and `x`, are respectively,

Options

A. `F_(2), Cl_(2)` and `Br_(2)`
B. `Cl_(2), F_(2)` and `Br_(2)`
C. `Cl_(2), Br_(2)` and `F_(2)`
D. `Br_(2), Cl_(2)` and `F_(2)`

Explanation

The electron affinity for halogens,
`F=332.6 ~~ 333 rArr Y`
`Cl =-348.5 ~~ -349 rArr X`
`Br = - 324.7 ~~ 325 rArr Z`
X has the highest value of electron affinity. Therefore, the correct order of electron affinity is
`Cl_(2)gt F_(2) gt Br_(2)`