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Solubility of BaF(2) in a solution of Ba...

Solubility of `BaF_(2)` in a solution of `Ba(NO_(3))_(2)`, will be represented by the concentration term:

A

`[Ba^(2+)]`

B

`[F^(-1)]^(2)`

C

`(1)/(2)[F^(-1)]`

D

`2[NO_(3)^(-)]`

Text Solution

Verified by Experts

The correct Answer is:
C
`Ba(NO_(3))_(2)` gives `Ba^(2+)` and `NO_(3)^(-)` ions, hence, concentration of `Ba^(2+)` ion increases. To keep `K_(sp)` constant, `[F^(-)]` decreases.
Thus, it is represented as `(1)/(2)[F^(-)]`
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