`pH` for the solution of salt undergoing anionic hydrolysis (say `CH_(3)COONa`) is given by:

Options

A. `pH = (1)/(2)pK_(a) -(1)/(2)pK_(b) +(1)/(2) log C`
B. `pH = (1)/(2)pK_(omega) +(1)/(2)pK_(a) - (1)/(2)pK_(b)`
C. `pH = (1)/(2)pK_(w) +(1)/(2)pK_(a) +(1)/(2)logC`
D. `pH = - (1)/(2)pK_(w) +(1)/(2)pK_(a) +(1)/(2)pK_(b)`

Answer

C

Explanation

For anionic hydrolysis,
`pH = (1)/(2) pK_(w) +(1)/(2)pK_(a) +(1)/(2)logC`