The expression for the solubility product of `Ag_(2)CrO_(3)` will be

Options

A. `K_(sp) = S^(2)`
B. `K_(sp) = 4S^(3)`
C. `K_(sp) = 27S^(4)`
D. `K_(sp) = S`

Answer

B

Explanation

`Ag_(2)CO_(3)(s) hArr underset(2s)(2Ag^(+)) + underset(s)(CO_(3)^(2-))`
`K_(sp) = [Ag^(+)]^(2) [CO_(3)^(2-)]`
`= (2S)^(2) S`
`K_(sp) = 4S^(3)`