The `[Ag^(+)]` ion in a saturated solution of `Ag_(2)CrO_(4)` at `25^(@)C is 1.5xx10^(-4)M`. Determine `K_(SP)` of `Ag_(2)CrO_(4)` at `25^(@)C`.

Options

A. `3.3750 xx 10^(-12)`
B. `1.6875 xx 10^(-10)`
C. `1.6875 xx 10^(-12)`
D. `1.6875 xx 10^(11)`

Answer

C

Explanation

`Ag_(2)CrO_(4) rarr 2Ag^(+) +CrO_(4)^(2-)`
`[CrO_(4)^(2-)] = (1)/(2)[Ag^(+)]`
`= (1.5 xx 10^(-4))/(2) = 0.75 xx 10^(-4)`
`K_(sp) = [Ag^(+)]^(2) [CrO_(4)^(2-)]`
`=(1.5 xx 10^(-4))^(2) (0.75 xx 10^(-4))`
`= 1.6875 xx 10^(-12)`