If the solubility of `Ag_(2)CrO_(4)` is S mol/L, its solubility product will be

Options

A. `S^(2)`
B. `S^(3)`
C. `4S^(3)`
D. `2S^(3)`

Answer

C

Explanation

`underset(S mol//L)(Ag_(2)CrO_(4)) hArr underset(2s)(2Ag^(+))+underset(S)(CrO_(4)^(2-))`
`K_(sp) = [Ag^(+)]^(2)[CrO_(4)^(2-)]`
`=(2S)^(2) (S) = 4S^(3)`