A sulphuric acid solution has `pH = 3`. Its normality is

Options

A. `1//1000`
B. `1//200`
C. `1//2000`
D. `1//100`

Answer

A

Explanation

`pH = 3`
`[H^(+)] = 1xx 10^(-3) mol//L`
`H_(2)SP_(4) rarr 2H^(+) +SO_(4)^(2-)`
`[H_(2)SO_(4)] = (1 xx 10^(-3))/(2) = (1)/(2000)M`
`N = 2M` (for `H_(2)SO_(4))`
Normality `= (2)/(2000) = (1)/(1000) N`