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[H^(+)] of 0.02 NCH(3) COOH which is 4% ...

`[H^(+)]` of `0.02 NCH_(3) COOH` which is `4%` dissociated, is

A

`0.08M`

B

`0.12 M`

C

`0.008M`

D

`0.8M`

Text Solution

Verified by Experts

The correct Answer is:
C
`alpha = 4% =(4)/(100) = 0.04`, Normality `=0.2`
`:. [H^(+)] = alpha xx N = 0.04 xx 0.2 = 0.008M`
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