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In acidic medium, equivalent weight of K...

In acidic medium, equivalent weight of `K_(2)Cr_(2)O_(7)` (molecular weight `= M`) is

A

`M//3`

B

`M//4`

C

`M//6`

D

`M//2`

Text Solution

Verified by Experts

The correct Answer is:
C
In acidic mediun, `K_(2)Cr_(2)O_(7)` gives following reaction,
`K_(2)overset(+6)(Cr_(2))O_(7) + 4H_(2)SO_(4) ("Dil.") rarrK_(2)SO_(4) + overset(+3)(Cr_(2)) (SO_(4))_(3) + 4H_(2)O + 3O_(2)`
`:.` Decrease in ON of Cr per atom `=3`
`:.` Decrease in ON of Cr per molecule `=2 xx 3 =6`
Hence, equivalent weight of `K_(2)Cr_(2)O_(7) = (M)/(6)`
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