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The oxidation number of sulphur in Na(2)...

The oxidation number of sulphur in `Na_(2)S_(4)O_(6)` is

A

`+6`

B

`+(3)/(2)`

C

`+(5)/(2)`

D

`-2`

Text Solution

Verified by Experts

The correct Answer is:
C
Oxidation number of `Na = +1`
Oxidation number of `O = -2`
Let oxidation number of `S = x`
`:. 2 (ON " of " Na) + 4 (ON " of " S) + 6(ON " of " O) = 0`
`2 (+1) + 4x + 6 (-2) = 0`
`+2 + 4x - 12 = 0`
`4x = + 12 - 2`
`x = + (10)/(4)`
`rArr x = + (5)/(2)`
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