In sulphur estimation, 0.157 g of an organic compound gives 0.4813 g of barium sulphate. The percentage of sulphur in the compound, is

Options

A. `42.10`
B. `52.10`
C. `21.05`
D. `40.01`

Answer

A

Explanation

Molecular mass of `BaSO_(4)=138 +32+64 = 233` g
23 g of `BaSO_(4)` contains 32 g of sulphur
`:. 0.4813 g` of `BaSO_(4)` will contain
`=(32 xx 0.4813)/(233)` g of sulphur
`%` of `S=(32 xx 0.4813xx100)/(233xx0.157)=42.10`.