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0.59 g of an organic compound produces 1...

0.59 g of an organic compound produces 112 mL nitrogen at NTP. The percentage of nitrogen in the compound through Duma's method is

A

23.7

B

27.5

C

33.07

D

16.8

Text Solution

Verified by Experts

The correct Answer is:
A
`%` of N through Duma's method is given by
`%` of `=N=(28xx"Volume of " N_(2)" at STP")/(22400 xx "Mass of an organic compound")xx100`
`=(28xx112xx100)/(22400xx0.59)=23.7`.
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