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The normality of 10% (weight/volume) ac...

The normality of 10% (weight/volume) acetic acid is

A

1 N

B

10 N

C

1.66 N

D

0.83 N

Text Solution

Verified by Experts

The correct Answer is:
c
Normality `= (w)/(E.V) = (10g)/(100 mL)xx(1)/(60)`
`= (10g)/((100)/(1000)xx60) = 1.66 N`
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