One litre of a solution of N/2 HCl was heated in beaker and it was observed that when the volume of solution got reduce to 600 mL, 3.25 g of HCl was lost. Calculate the normality of the resulting solution.

Options

A. 0.50 N
B. 0.60 N
C. 0.68 N
D. 0.70 N

Answer

c

Explanation

1 L of N/2 HCl contains `= (1)/(2)xx36.5 = 18.25 g`
HCl now present `= 18.25 - 3.25 = 15 g`
Now, volume = 600 mL = 0.600 L
Normality `= (15)/(36.5)xx(1)/(0.600 L) = 0.685 N`