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The relative lowering of vapour pressure...

The relative lowering of vapour pressure of an aqueous solution containing a non-volatile solute, is 0.0125. The molality of the solution is

A

0.69 m

B

0.50 m

C

0.80 m

D

0.40 m

Text Solution

Verified by Experts

The correct Answer is:
a

`(p_(@) - p_(s))/(p_(@)) = (mxxM)/(1000)`
`0.0125 = (mxx18)` (molecular weight of `H_(2)O = 18`)
`m = (0.0125xx1000)/(18) = 0.69`
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