The latent heat of vaporisation of water...

The latent heat of vaporisation of water is `9700 "Cal/mole"` and if the b.p.is `100^(@)C`, ebullioscopic constant of water is

`0.516^(@)C`

`1.026^(@)C`

`10.26^(@)C`

`1.832^(@)C`

Text Solution

Verified by Experts

The correct Answer is:

`K_(b) = (R.T_(b)^(2))/(1000.L_(V)) = (2xx373xx373xx18)/(1000xx9700) = 0.516^(@)C`

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