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The freezing point (in .^@C) of solution...

The freezing point (in `.^@C`) of solution containing 0.1 g of `K_(3)[Fe(CN)_(6)]` (molecular weight 329) in 100 g of water `(K_(f) = 1.86 K kg mol^(-1))` is

A

`-2.3xx10^(-2)`

B

`-5.7xx10^(-2)`

C

`-5.7xx10^(-3)`

D

`-1.2xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
a

van't Hoff factor (i) `= 4{3K^(+) + Fe(CN)_(6))^(3-)}`
Molality `= (0.1xx1000)/(329xx100) = (1)/(329)`
`-DeltaT_(f) = iK_(f)m = 4xx1.86xx(1)/(329) = 2.3xx10^(-2)`
`rArr DeltaT_(f) = -2.3xx10^(-2)C`
(As freezing point of water is `0^(@)C`)
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The freezing point (.^(@)C) of a solution containing 0.1 g of K_(3)[Fe(CN)_(6)] (molecular weight 329) on 100 g of water (K_(f)=1.86 K kg mol^(-1))

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