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The value of Lambda(eq)^(oo) for NH(4)Cl...

The value of `Lambda_(eq)^(oo)` for `NH_(4)Cl, NaOH` and `NaCl` are `149.74, 248.1` and `126.4 Omega^(-1) cm^(2)" equiv"^(-1)`. The value of `Lambda_(eq)^(oo)` of `NH_(4)OH` is

A

`371,44 Omega cm^(2)" equiv"^(-1)`

B

`271,44 Omega cm^(2)" equiv"^(-1)`

C

`71,44 Omega cm^(2)" equiv"^(-1)`

D

data is insufficient to calculate it

Text Solution

Verified by Experts

The correct Answer is:
B
`Lambda_(eq)^(oo) (NH_(4)OH)=Lambda_(eq)^(oo)(NH_(4)Cl)+ Lambda_(eq)^(oo) NaOH-Lambda_(eq)^(oo) (NaCl)`
`=(149.74+248.1)-126.4`
`=271.44 Omega cm^(2)" equiv"^(-1)`
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