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The charge required for the reduction of...

The charge required for the reduction of 1 mole of `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` is

A

96500 C

B

`2xx96500 C`

C

`3 xx96500 C`

D

`6xx96500 C`

Text Solution

Verified by Experts

The correct Answer is:
D
`overset(+6)(Cr_(2))overset(-2)(O_(7)) rarr overset(+3)(Cr)`
Hence, electrons involved in this reduction will be
`=2xx[(+6)-(+3)]=2xx3=6`
`:.` Charge required for one mole `=6xx96500 C`
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