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A certain amount of current liberates 0....

A certain amount of current liberates 0.5 g of `H_(2)` in 2.0 h. How many gram(s) of oxygen can be liberated by the same current in the same time?

A

0.5 g

B

8.0 g

C

4.0 g

D

16.0 g

Text Solution

Verified by Experts

The correct Answer is:
C
According to Faraday's first law, `w=Zit`
Given, it is same for `H_(2)` and `O_(2)`.
`W_(H_(2))/W_(O_(2))=Z_(H_(2))/Z_(O_(2))=E_(H_(2))/E_(O_(2))`
`0.500/W_(O_(2))=2/16, W_(O_(2))=4.00 g`
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