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A cell constituted by two electrondes A(...

A cell constituted by two electrondes `A(E_(A//A^(+))^(@)= -0.35 V)` and `B (E_(B//B^(+))^(@)=0.42 V)`.
Calculate the emf of the cell.

A

0.07 V

B

0.77 V

C

`-0.77 V`

D

`-0.07 V`

Text Solution

Verified by Experts

The correct Answer is:
B
Since, reduction potential of electrode, A is lower than that of B.
We have, `E_("cell")^(@)=E_("cathode")^(@)-E_("anode")^(@)`
`=0.42-(-0.35)=0.77 V`
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