The emf of the cell involving the reaction
`2Ag^(+) (aq)+H_(2)(g) rarr 2Ag(s)+2H^(+) (aq)` is `0.080 V`.
The standard oxidation potential od silver electrode is

Options

A. 0.80 V
B. 0.40 V
C. `-0.80 V`
D. 0.20 V

Answer

C

Explanation

From the equation, give cell represented as
`H_(2)|H^(+) (aq) ||Ag^(+) (aq)| Ag`
Hence, `E_("cell")=E_(Ag^(+)//Ag)-E_(H^(+)//1/2 H_(2))`
or `0.80=E_(Ag^(+)//Ag)-0.0`
`:. E_(Ag^(+)//Ag)=0.80 V`
Hence, `E_("oxi")=-0.80 V`