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The molar conducatance of Ba^(2+) and Cl...

The molar conducatance of `Ba^(2+)` and `Cl^(-)` are `127` and `76 ohm^(-1) cm^(-1) mol^(-1)` respectively at infinite dilution. The equivalent conductance of `BaCl_(2)` at infinte dilution will be

A

`330 Omega^(-1) cm^(2)`

B

`203 Omega^(-1) cm^(2)`

C

`139.5 Omega^(-1) cm^(2)`

D

`51 Omega^(-1) cm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`Lambda_(m)^(oo)` for `BaCl_(2)=Lambda_(m)^(oo) Ba^(2+)+2Lambda_(m)^(oo)Cl^(-)`
`:. Lambda_(eq)^(oo)` for `BaCl_(2)=1/2 Lambda_(m)^(oo)Ba^(2+)+Lambda_(m)^(oo)Cl^(-)`
`=1/2 xx127+76=139.5 Omega^(-1) cm^(2)`
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