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A curent of 0.5 A when passed through Ag...

A curent of 0.5 A when passed through `AgNO_(3)` solution for 193 s deposited 0.108 h Ag. The equivalent weight of silver is

A

108

B

54

C

10.8

D

5.4

Text Solution

Verified by Experts

The correct Answer is:
A
`w=(ixxtxxE)/(F)implies E=(wxxF)/(ixxt)`
`=(0.108xx96500)/(0.5xx193)=108`
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