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The standard potential of the reaction ...

The standard potential of the reaction
`H_(2)O + e^(-) rightarrow (1/2)H_(2) + OH^(-)` at 298 K by using `k_(w) (H_(2)O) = 10^(-14)`, is:

A

`E^(@)=(RT)/(F) ln K_(w)`

B

`E^(@)=(RT)/(F) "ln "[p_(H_(2))]^(1//2) [OH^(-)]`

C

`E^(@)=(RT)/(F) "ln "([p_(H_(2))]^(1//2))/([H^(+)])`

D

`E^(@)=- (RT)/(F) ln K_(W)`

Text Solution

Verified by Experts

The correct Answer is:
A
The standard reduction potential of the cell reaction is
`E^(0)=(RT)/(F) ln K_(w)`
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