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The minimum voltage required to electrol...

The minimum voltage required to electrolyse alumina in the Hall-Heroul process is [Given, `DeltaG^(@)_(f)(A1_(2)O_(3)) =- 1520kJ//mol` and `DeltaG^(@)_(f)(CO_(2)) = 394kJ//mol]`

A

`0.8 V`

B

`1,60 V`

C

`2.8 V`

D

`3.0 V`

Text Solution

Verified by Experts

`(b) 2AI_(2)O_(3)+3C to 4AI + 3CO_(2)`
`Delta_(f)G^(@)=3DeltaG^(@)(CO_(2))`
`=3xx(-394)-2xx(-1520)=1859kJ`
`=1858xx10^(3)J`
`:. nFE^(@) = 1858 xx 10^(3)" "(n=12 "electrons")`
`:. E^(@)=(1858xx10^(3))/(12xx96500)=1.60 V`
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