The reaction,
`C_(6)H_(5)Br+2Na+BrCH_(3) rarr C_(6)H_(5).CH_(3)+2NaBr` is known as

Options

A. Wurtz reaction
B. Wurtz-Fitting reaction
C. Friedel-Crafts reaction
D. Berthelot synthesis

Explanation

To solve the question regarding the reaction of bromobenzene with sodium and bromoethane, we can break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in the given reaction are bromobenzene (C₆H₅Br) and bromoethane (BrCH₃).

2. **Recognize the Reaction Type**:
This reaction is a type of coupling reaction where an aromatic halide (bromobenzene) reacts with an alkyl halide (bromoethane) in the presence of sodium.

3. **Understand the Role of Sodium**:
Sodium acts as a reducing agent in this reaction. It helps in the formation of a carbon-carbon bond between the aromatic compound and the alkyl halide.

4. **Reaction Mechanism**:
- The sodium donates electrons to the bromobenzene, replacing the bromine atom and forming a phenyl radical (C₆H₅·).
- The phenyl radical then reacts with the alkyl halide (bromoethane) to form toluene (C₆H₅CH₃) and sodium bromide (NaBr).

5. **Write the Balanced Reaction**:
The balanced chemical equation for the reaction is:
\[ C_6H_5Br + 2Na + BrCH_3 \rightarrow C_6H_5CH_3 + 2NaBr \]

6. **Name the Reaction**:
This reaction is known as the **Wurtz Reaction**. It is specifically a coupling reaction of an aromatic halide with an alkyl halide in the presence of sodium.

### Final Answer:
The reaction is known as the **Wurtz Reaction**.

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