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The major product of reaction between n-...

The major product of reaction between n-butane and bromine at `130^(@)C` is

A

`CH_(3)CH_(2)CH_(2)CH_(2)Br`

B

`CH_(3)CH_(2)underset(CH_(3))underset(|)(CH)Br`

C

`CH_(3)-underset(CH_(2)Br)underset(|)(CH_(2))CHBr`

D

`CH_(3)CH_(2)underset(CH_(3))underset(|)(CH)Br`

Text Solution

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The correct Answer is:
To determine the major product of the reaction between n-butane and bromine at 130°C, we can follow these steps: ### Step 1: Understand the Reactants - **Identify n-butane**: n-butane (C4H10) has the structure CH3-CH2-CH2-CH3. - **Identify bromine**: Bromine (Br2) is a diatomic molecule that can participate in substitution reactions. ### Step 2: Reaction Conditions - The reaction occurs at a high temperature (130°C), which favors radical reactions, specifically free radical bromination. ### Step 3: Initiation of the Reaction - The reaction begins with the homolytic cleavage of the Br-Br bond, generating two bromine radicals (Br•). ### Step 4: Propagation Steps - The bromine radical can abstract a hydrogen atom from n-butane, forming a butyl radical and HBr. - The butyl radical can be either a primary (1°) or a secondary (2°) radical, depending on which hydrogen is abstracted. ### Step 5: Formation of Radicals - **Primary Radical**: If a hydrogen from the terminal carbon is removed, a primary butyl radical (CH3-CH2-CH2-CH2•) is formed. - **Secondary Radical**: If a hydrogen from the second carbon is removed, a more stable secondary butyl radical (CH3-CH2-CH•-CH3) is formed. ### Step 6: Stability of Radicals - The secondary radical is more stable than the primary radical due to hyperconjugation and the inductive effect of the adjacent carbon atoms. ### Step 7: Termination Steps - The secondary butyl radical can react with another bromine radical to form the major product: CH3-CH2-CHBr-CH3 (2-bromobutane). - The primary radical can also react with a bromine radical, but it will yield a less stable product: CH3-CH2-CH2-CH2Br (1-bromobutane). ### Conclusion - The major product of the reaction between n-butane and bromine at 130°C is 2-bromobutane (CH3-CH2-CHBr-CH3). ### Final Answer The major product is **2-bromobutane**. ---

To determine the major product of the reaction between n-butane and bromine at 130°C, we can follow these steps: ### Step 1: Understand the Reactants - **Identify n-butane**: n-butane (C4H10) has the structure CH3-CH2-CH2-CH3. - **Identify bromine**: Bromine (Br2) is a diatomic molecule that can participate in substitution reactions. ### Step 2: Reaction Conditions - The reaction occurs at a high temperature (130°C), which favors radical reactions, specifically free radical bromination. ...
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