Which of the following is the predominant product in the reaction of HOBr with propene?

Options

A. 2-bromo-1-propanol
B. 3-bromo-1-propanol
C. 2-bromo-2-propanol
D. 1-bromo-2-propanol

Explanation

To determine the predominant product in the reaction of HOBr with propene, we can follow these steps:

### Step 1: Identify the Reactants
We start with propene (C3H6), which has a double bond between two carbon atoms. The structure of propene can be represented as:
```
H H
\ /
C
/ \
H C
|
H
```
We are reacting it with HOBr.

### Step 2: Understand the Dissociation of HOBr
HOBr dissociates into two parts: hydroxyl (OH) and bromine (Br). This means we will have:
- OH (hydroxyl group)
- Br (bromine atom)

### Step 3: Apply Markovnikov's Rule
According to Markovnikov's rule, when HX (where X is a halogen) reacts with an alkene, the hydrogen atom (H) will attach to the carbon with the greater number of hydrogen atoms (the less substituted carbon), while the halogen (Br) will attach to the more substituted carbon.

In propene, the double bond is between the first and second carbon atoms. The carbon atoms can be labeled as follows:
- C1: CH2
- C2: CH
- C3: CH3

When HOBr is added to propene, the double bond opens up, and the OH group will attach to the more substituted carbon (C2), while the Br will attach to the less substituted carbon (C1).

### Step 4: Determine the Product Structure
Following the application of Markovnikov's rule:
- OH will attach to C2 (the more substituted carbon).
- Br will attach to C1 (the less substituted carbon).

The product can be represented as:
```
H OH
\ /
C
/ \
H C
|
Br
```
This gives us the structure of 2-bromopropanol.

### Step 5: Conclusion
The predominant product of the reaction between HOBr and propene is 2-bromopropanol.

### Final Answer
The correct answer is **2-bromopropanol**.

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