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Consider the following reaction, (CH(3...

Consider the following reaction,
`(CH_(3))_(3)C-Cl+OHrarr(CH_(3))_(3)C-OH+Cl^(-)`
The true statement about the above process is

A

the rate becomes four times of the halide becomes twice

B

the rate does not change by reducing `[OH^(-)]` to half

C

the rate does not change by doubling [halide]

D

the rate becomes twice on doubling the `[OH^(-)]`

Text Solution

Verified by Experts

The correct Answer is:
B
`S_(N)1` reaction depends only upon concentration of substrate.
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