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Consider the following reaction, CH(3)...

Consider the following reaction,
`CH_(3)Br+OH^(-)rarrCH_(3)OH+Br^(-)`
The true statement about the above process is

A

the rate does not change on doubling `[CH_(3)Br]` and making `[OH^(-)]` to half

B

the rate becomes half on doubling `[CH_(3)Br]`

C

the rate becomes half on doubling `[OH^(-)]`

D

All the above are correct

Text Solution

Verified by Experts

The correct Answer is:
A
`S_(N)2` reaction rate is directly proportional to connectration of substrate and nucleophile.
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