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2-bromopentane with alcoholic KOH yields...

2-bromopentane with alcoholic KOH yields a mixture of three alkenes. Which of the following alkene is predominant?

A

1-pentene

B

Cis-2-pentene

C

Trans-2-pentene

D

Cis-1-pentene

Text Solution

Verified by Experts

The correct Answer is:
C
`CH_(3)CH_(2)CH_(2)underset(Br)underset(|)(CH)CH_(3)overset(Alc.KOH)rarrCH_(3)CH_(2)CH_(2)CH=CH_(3)CH_(2)CH=CHCH_(3)`
By Saytzeff's rule, substituted alkenes are more stable.
Hence, out of cis and trans forms, trans product is more stable.
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