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The standard potential E^(@) for the hal...

The standard potential `E^(@)` for the half reactions are as `:`
`Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V`
`Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V `
The standard cell voltage for the cell reaction is ?
`Zn +Cu^(2) rarr Zn ^(2+) +Cu`

A

0.42V

B

`-0.42 v `

C

`-1.1V`

D

1.10V

Text Solution

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The correct Answer is:
D
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The standard reduction potential E^(@) , for the half reaction are : {:(Zn rarr Zn^(2+) + 2e^(-),,,E^(@) = 0.76 V),(Cu rarr Cu^(2+) + 2e^(-),,,E^(@) = 0.34 V):} The emf for the cell reaction, Zn(s)+Cu^(2+) rarr Zn^(2+) + Cu(s) is :

The standard oxidation potentials, , for the half reactions are as follows : Zn rightarrow Zn^(2+) + 2e^(-) , E^(@) = +0.76V Fe rightarrow Fe^(2+)+ 2e^(-), E^(@) = + 0.41 V The EMF for the cell reaction, Fe^(2+) + Zn rightarrow Zn^(2+) + Fe

The standard oxidation potentials, E^(@) , for the half reactions are as, Zn rarr Zn^(2+) + 2e^(-), " " E^(@) = + 0.76 volt Fe rarr Fe^(2+) + 2e^(-), " " E^(@) = +0.41 volt The emf of the cell, Fe^(2+) + Zn rarr Zn^(2+) + Fe is:

The standard oxidation potential, E^(@) , for the reactions are given as: Zn rightarrow Zn^(2+) + 2e^(-) , E^(@) = +0.76V Fe rightarrow Fe^(2+) + 2e^(-) , E^(@) = +0.41V The emf for the cell : Fe^(2+) + Zn rightarrow Zn^(2+) + Fe

The standard oxidation potential E^@ for the half cell reaction are Zn rarr Zn^2+2e^- E^@=+ 0.76 V Fe rarr Fe^2+ + 2e^- E^@=+ 0.41 V EMF of the cell rection is Zn+Fe^(2+) rarr Zn^(2+)+Fe

Electrode potential for the following half-cell reactions are Zn rarr Zn^(2+)+2e^(-), E^(@)=+0.76V, Fe rarr Fe^(2+)+2e^(-), E^(@)=+0.44V The EMF for the cell reaction Fe^(2+)+Zn rarr Zn^(2+)+Fe will be

Reduction potential for the following h alf-cell reaction are Zn rarr Zn rarr Zn^(2+)+2e^(-),E_(Zn^(2+)//Zn)^(@) = -0.76V Fe rarr Fe^(2+)+2e^(-),E_(Fe^(2+)//Fe)^(@) = -0.76V The emf for the cell reaction Fe^(2+)Zn rarr Zn^(2+)+Fe will be

The standared reduction potntial E^o for the half-reactions are as. Zn=Zn^(2+) + 2 e^- , E^o = + 76 V Fe = Fe^(2+) + 2e^- , E^o = + 0.41 V . The EMF for cell recaction Fe^(2+) = Zn rarr Zn^(2+) + Fe is.

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