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In Wheatstone bridge, four resistors of ...

In Wheatstone bridge, four resistors of resistances `15 Omega, 12 Omega, 4Omega` and `10 Omega` respectively, are connected in cyclic order. The resistance ( in `Omega `) that is to be connected in parallel with the resistance of `10 Omega` to balance the network is

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Four resistances of 15Omega,12Omega,4Omega and 10Omega respectively are connected in cyclic order to form a wheatstone bridge. Is the network balanced? If not, calculate the resistance to be connected in parallel with the resistance of 10Omega to balance the network

Four resistances of 16 Omega , 12 Omega , 4 Omega and 9 Omega respectively are connected in cycle order so from a Wheatstone bridge. Calculate the resistance in be connected in parallel with 9 Omega resistance to balance the bridge.

Knowledge Check

  • The resistors of resistances 2 Omega, 4 Omega and 8 Omega are connected in parallel, then the equivalent resistance of the combination will be

    A
    `(8)/(7) Omega`
    B
    `(7)/(8)Omega`
    C
    `(7)/(4)Omega`
    D
    `(4)/(9)Omega`
  • If three resistors of resistance 2Omega, 4Omega and 5 Omega are connected in parallel then the total resistance of the combination will be

    A
    `(20)/(19)Omega`
    B
    `(19)/(20)Omega`
    C
    `(19)/(10)Omega`
    D
    `(10)/(19)Omega`
  • Four resistances of 3Omega, 3Omega, 3Omega and 4Omega respectively are used to form a Wheatstone bridge. The 4Omega resistance is short circuited with a resistance R in order to get bridge balanced. The value of R will be

    A
    `10Omega`
    B
    `11Omega`
    C
    `12Omega`
    D
    `13Omega`
  • Similar Questions

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    In a circuit four resistors of 1 Omega ,2 Omega, 6 Omega and 12 Omega respectively are connected in series combination. The maximum resistance that can be obtained is

    If Four resistors each of 1 Omega are connected in parallel the effective resistances will be

    Three resistors, each of resistance 12 Omega , are connected in parallel. What is the equivalent resistance ?

    Three resistances of 2 Omega, 3 Omega and 6 Omega are first connected in series and the equivalent resistance is found to be……… Then the three resistances are connected in parallel Now its equivalent resistance is………

    Three resistors of resistance 2 Omega,5 Omega and 3 Omega respectively are connected in parallel across a battery of 10 volts and negligible resistance. The potential difference across 5 Omega resistor is