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Evaluate: int(cos4x-cos2x)/(sin4x-sin2x)...

Evaluate: `int(cos4x-cos2x)/(sin4x-sin2x)dx`

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To evaluate the integral \[ \int \frac{\cos 4x - \cos 2x}{\sin 4x - \sin 2x} \, dx, \] we will simplify the integrand first. ...
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Knowledge Check

  • int(cos^3x+cos^5x)/(sin^2x+sin^4x)dx=

    A
    `sinx-2/(sinx)+5tan^(-1)(sinx)`
    B
    `sinx-6tan^(-1)(sinx)`
    C
    `sinx-2/(sinx)`
    D
    `sinx-2/(sinx)-6tan^(-1)(sinx)`

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