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Evaluate: int(cos4x-cos2x)/(sin4x-sin2x)...

Evaluate: `int(cos4x-cos2x)/(sin4x-sin2x)dx`

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To evaluate the integral \[ \int \frac{\cos 4x - \cos 2x}{\sin 4x - \sin 2x} \, dx, \] we will simplify the integrand first. ...
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