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Evaluate: int1/(a^2-b^2x^2)dx...

Evaluate: `int1/(a^2-b^2x^2)dx`

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`int1/(a^2-b^2x^2)dx`
`= int1/(a^2-(bx)^2)dx`
Let `t=bx=>dt=bdx`
`=frac{1}{b}int1/(a^2-t^2)dx`
We know that, `int frac{dx}{a^2-x^2}=frac{1}{2a}log abs(frac{a+x}{a-x})+C`
Let, `x=t`
`=frac{1}{b}xx frac{1}{2a}log abs(frac{a+t}{a-t})+C`
`=frac{1}{2ab}log abs(frac{a+t}{a-t})+C` ...
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