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Evaluate: int(x+1)/(x^2+x+3)dx...

Evaluate: `int(x+1)/(x^2+x+3)dx`

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`(x+1)/(x^2+x+3)=A/(x-2)+B/(x-3)=frac{A(x-3)+B(x-2)}{(x-2)(x-3)}`
`x-1=x(A+B)-(3A+2B)`
`A+B=1 ---(1)`
`3A+2B=1 ---(2)`
Solving 1 and 2, we get, `A=-1` and `B=2`
`int(x+1)/(x^2+x+3)dx=2 int frac{dx}{x-3}-int frac{dx}{x-2}`
`=2 ln abs(x-3)-ln abs(x-2)+C`
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