[6(ax+by)=3a+2b],[6(bx-ay)=3b-2a]

Solve the following system of equations by method of cross-multiplication: 6(ax+by)=3a+2b,quad 6(bx-ay)=3b-2a

(ax+by)^(2)+(bx-ay)^(2)

2(ax-by)+(a+4b)=0,2(bx+ay)+(b-4a)=0

Fractorise: (ax + by) ^(2) + (bx - ay)^(2)

ax+by=a-b;bx-ay=a+b

2 (ax+by)^(2)-(bx+ay)^(2)

Factorise : (v) (ax + by )^(2) + (bx - ay)^(2)

Solve: ax + by = a - b bx - ay = a + b

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}