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" (a) "(1+sec A)/(sec A)=(sin^(2)theta)/...

" (a) "(1+sec A)/(sec A)=(sin^(2)theta)/(1-cos A)

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(1+sec A)/(sec A)=(sin^(2)A)/(1-cos A)

Prove: (1+sec theta)/(sec theta)=(sin^(2)theta)/(1-cos theta)

Prove each of the following identities : (i) (sec theta -1)/(sec theta +1) =(sin^(2) theta)/((1+ cos theta)^(2) ) (ii) (sec theta - tan theta)/(sec theta + tan theta) = (cos^(2) theta)/((1+ sintheta)^(2))

(1 + sec A ) / ( sec A ) = ( sin ^ 2 A ) /( 1 - cos A )

Prove that (1 + sec theta) / sec theta = sin^2 theta /(1 - cos theta)

Prove that: (sec theta-1)/(sec theta+1)=((sin theta)/(1+cos theta))^(2)

1-(sin^(2) theta)/(1+cos theta) + (1+cos theta)/(sin theta) - (sin theta)/(1-cos theta) - (1)/(sec theta)=

Prove that (1+ cot theta + tan theta ) ( sin theta - cos theta) = (sec theta )/(cosec^(2) theta) - (cosec theta)/(sec^(2)theta) .

(tan theta)/(sec theta-1)-(sin theta)/(1+cos theta)=2cot theta

Show that (tan theta+sec theta -1)/(tan theta - sec theta +1)=(1 + sin theta)/(cos theta)