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Evaluate: int(x^2+x+1)/(x^2-x)dx...

Evaluate: `int(x^2+x+1)/(x^2-x)dx`

Text Solution

Verified by Experts

Given
`int(x^2+x+1)/(x^2-x)dx`
so,`int(x^2+x+1)/(x^2-x)dx=1+(2x+1)/(x^2-x)`
thus,`int(2x+1)/(x^2-x)dx=A/x+B/(x-1)`
Cancelling denominator
`2x+1=Ax+Bx-A`
or,`A=-1 `and `B=3`
substituting we get,
...
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