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Evaluate: int(cotx)/(logsinx)dx...

Evaluate: `int(cotx)/(logsinx)dx`

Text Solution

Verified by Experts

I=`int(cotx)/(logsinx)dx`
Let `cotx=t`
`logsinxdx=dt`
`I=int tdt`
=`t^2/2+c`
=`(cotx)^2/2+c`
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