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Evaluate: int(sinx-cosx)/(sqrt(sin2x))dx...

Evaluate: `int(sinx-cosx)/(sqrt(sin2x))dx`

Text Solution

Verified by Experts

I=`int(sinx-cosx)/(sqrt(sin2x))dx`
Put
`sinx−cosx=t`
`(sinx+cosx)dx=dt`
`t^2=1−sin2x`
=`sin2x=1−t^2`
Thus,`dt/sqrt(1-t^2)`
=`sin^(−1)t+c`
...
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