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int (sin2x)/(sin^4x+cos^4x) dx...

`int (sin2x)/(sin^4x+cos^4x) dx`

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We have given
`int (sin2x)/(sin^4x+cos^4x) dx`
`I=int (sin2x)/(sin^4x+cos^4x) dx`
Dividing the numerator and denominator by `cos^4x`
`int (2tanx×sec^2x )/(tan^4x+1) dx`
Let `tanx=u`
`(sec^2x)dx=du`
`int (2u)/(1+u^2) dx`
...
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