" (i) "3x+5y=7.5

Two consecutive sides of a parallelogram are 4x+5y=0a d n7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) 3x + 5y + 5 =0

Find the value of (x+y) ,if 3x+5y=9,5x+3y=7

x-2/3 y=8/3; (2x)/5-y=7/5

5) 3x-4y=-7;5x-2y=0 find x and y

The equation of the line passing through (1,5) and perpendicular to the line 3x-5y+7=0 is 5x+3y-20=0 b. 3x-5y+7=0 c. 3x-5y+6=0 d. 5x+3y+7=0

The equation of the line passing through (1,5) and perpendicular to the line 3x-5y+7=0 is a. 5x+3y-20=0 b. 3x-5y+7=0 c. 3x-5y+6=0 d. 5x+3y+7=0

If (7x+5y) :(3x + 9y) = 5 : 7 , then x : y =

{:(2x - 4y = 3),(5x - ky = 7.5):}