Evaluate: `intx(1-x)^(23)dx`

Explanation

`intx(1-x)^(23)dx`

Let `t=1−x=>dt=−dx`

`impliesx=1−t`

`I=-int(1−t)t^23dt`

`I=-int(t^23−t^24)dt`

`I=-(t^(23+1))/(23+1)+(t^(24+1))/(24+1)+c`

`I=-t^(24)/(24)+(t^(25))/(25)+c`

`I=-(1-x)^(24)/(24)+((1-x)^(25))/(25)+c`

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