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Evaluate: int(cotx)/(sinx)dx...

Evaluate: `int(cotx)/(sinx)dx`

Text Solution

Verified by Experts

I=`int(cotx)/(sinx)dx`
I=`int(cosx)/(sinxsinx)dx`
let `sinx=t`
`cosxdx=dt`
I=`int dt/t^2`
=`t^(-1)/(-1)+c`
=`-t^(-1)+c`
...
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