If `y=a x^2+b x+c` represents the curve given in the figure and `b^2=2(b+2a c),` where `a!=0` and `A P=3` units, then `O P=` `3/2` (b) `3/4` (c) 3 (d) 6

If y=ax^(2)+bx+c represents the curve given in the figure and b^(2)=2(b+2ac) where a!=0 and AP=3 units,then OP=(3)/(2) (b) (3)/(4)(c)3(d)6

If a/2 = b/3 = c/4 = (2a - 3b + 4c)/p , then find the value of P .

a,b,c are in G.P. and a+b+c=xb , x can not be (a) 2 (b) -2 (c) 3 (d) 4

a,b,c are in G.P. and a+b+c=xb, x can not be (a) 2 (b) -2 (c) 3 (d) 4

If a ,b and c are in A.P. and b-a ,c-b and a are in G.P., then a : b : c is (a). 1:2:3 (b). 1:3:5 (c). 2:3:4 (d). 1:2:4

If a ,b and c are in A.P. and b-a ,c-b and a are in G.P., then a : b : c is (a). 1:2:3 (b). 1:3:5 (c). 2:3:4 (d). 1:2:4

If a variable tangent to the curve x^2y=c^3 makes intercepts a , b on x a n d y-a x e s , respectively, then the value of a^2b is (a) 27c^3 (b) 4/(27)c^3 (c) (27)/4c^3 (d) 4/9c^3

If a/2 = b/3 = c/4 = 2a-3b+4c/p, then find p .

If a!=0 and the line 2b x+3c y+4d=0 passes through the points of intersection of the parabolas y^2=4a x and x^2=4a y , then (a) d^2+(2b+3c)^2=0 (b) d^2+(3b+2c)^2=0 (c) d^2+(2b-3c)^2=0 (d)none of these

If a!=0 and the line 2b x+3c y+4d=0 passes through the points of intersection of the parabolas y^2=4a x and x^2=4a y , then (a) d^2+(2b+3c)^2=0 (b) d^2+(3b+2c)^2=0 (c) d^2+(2b-3c)^2=0 (d)none of these