the distance `s` meters travelled in time `t` second by a car is given by the relation `s=3t^2` then find the velocity of the car at time `t=4 seconds.

The distance s feet travelled by a particle in time t seconds is given by s = t^(3) - 6 t^(2) - 4t - 8 . Its acceleration vanishes at time t =

The distance s feet travelled by a particle in time t second is given by s = t^3 - 6t^2 - 4t -8 . It acceleration vanishes at time t =

The distance s feet travelled by a particle in time t seconds is given by s=t^3-6t^2-4t-8 . It's acceleration vanishes at time t =

The displacement s of a particle at time t is is given by s=2 t^3 - 4 t^2 -5t. Then find the velocity at t=2 sec

If the distance s travelled by a particle in time t is given by s=t^2-2t+5 , then its acceleration is

The distance in meters described by a car in time t seconds is given by s = 4t^(3) - 3t^(2) + 6t -1 . Determine the velocity and acceleration when (i) t = 0, (ii) t =2 seconds.